Integrand size = 15, antiderivative size = 34 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=-\frac {\text {arctanh}(\sin (a+b x))}{2 b}+\frac {\sec (a+b x) \tan (a+b x)}{2 b} \]
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Time = 0.03 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2691, 3855} \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=\frac {\tan (a+b x) \sec (a+b x)}{2 b}-\frac {\text {arctanh}(\sin (a+b x))}{2 b} \]
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Rule 2691
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {\sec (a+b x) \tan (a+b x)}{2 b}-\frac {1}{2} \int \sec (a+b x) \, dx \\ & = -\frac {\text {arctanh}(\sin (a+b x))}{2 b}+\frac {\sec (a+b x) \tan (a+b x)}{2 b} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.00 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=-\frac {\text {arctanh}(\sin (a+b x))}{2 b}+\frac {\sec (a+b x) \tan (a+b x)}{2 b} \]
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Time = 0.11 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.41
method | result | size |
derivativedivides | \(\frac {\frac {\sin ^{3}\left (b x +a \right )}{2 \cos \left (b x +a \right )^{2}}+\frac {\sin \left (b x +a \right )}{2}-\frac {\ln \left (\sec \left (b x +a \right )+\tan \left (b x +a \right )\right )}{2}}{b}\) | \(48\) |
default | \(\frac {\frac {\sin ^{3}\left (b x +a \right )}{2 \cos \left (b x +a \right )^{2}}+\frac {\sin \left (b x +a \right )}{2}-\frac {\ln \left (\sec \left (b x +a \right )+\tan \left (b x +a \right )\right )}{2}}{b}\) | \(48\) |
risch | \(-\frac {i \left ({\mathrm e}^{3 i \left (b x +a \right )}-{\mathrm e}^{i \left (b x +a \right )}\right )}{b \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{i \left (b x +a \right )}+i\right )}{2 b}+\frac {\ln \left ({\mathrm e}^{i \left (b x +a \right )}-i\right )}{2 b}\) | \(78\) |
parallelrisch | \(\frac {\left (1+\cos \left (2 b x +2 a \right )\right ) \ln \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )-1\right )+\left (-1-\cos \left (2 b x +2 a \right )\right ) \ln \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )+1\right )+2 \sin \left (b x +a \right )}{2 b \left (1+\cos \left (2 b x +2 a \right )\right )}\) | \(78\) |
norman | \(\frac {\frac {\tan \left (\frac {b x}{2}+\frac {a}{2}\right )}{b}+\frac {\tan ^{3}\left (\frac {b x}{2}+\frac {a}{2}\right )}{b}}{\left (\tan ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )-1\right )^{2}}+\frac {\ln \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )-1\right )}{2 b}-\frac {\ln \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )+1\right )}{2 b}\) | \(81\) |
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Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (30) = 60\).
Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.79 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=-\frac {\cos \left (b x + a\right )^{2} \log \left (\sin \left (b x + a\right ) + 1\right ) - \cos \left (b x + a\right )^{2} \log \left (-\sin \left (b x + a\right ) + 1\right ) - 2 \, \sin \left (b x + a\right )}{4 \, b \cos \left (b x + a\right )^{2}} \]
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\[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=\int \sin ^{2}{\left (a + b x \right )} \sec ^{3}{\left (a + b x \right )}\, dx \]
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none
Time = 0.19 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.35 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=-\frac {\frac {2 \, \sin \left (b x + a\right )}{\sin \left (b x + a\right )^{2} - 1} + \log \left (\sin \left (b x + a\right ) + 1\right ) - \log \left (\sin \left (b x + a\right ) - 1\right )}{4 \, b} \]
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none
Time = 0.33 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.41 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=-\frac {\frac {2 \, \sin \left (b x + a\right )}{\sin \left (b x + a\right )^{2} - 1} + \log \left ({\left | \sin \left (b x + a\right ) + 1 \right |}\right ) - \log \left ({\left | \sin \left (b x + a\right ) - 1 \right |}\right )}{4 \, b} \]
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Time = 0.55 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.03 \[ \int \sec (a+b x) \tan ^2(a+b x) \, dx=\frac {{\mathrm {tan}\left (\frac {a}{2}+\frac {b\,x}{2}\right )}^3+\mathrm {tan}\left (\frac {a}{2}+\frac {b\,x}{2}\right )}{b\,\left ({\mathrm {tan}\left (\frac {a}{2}+\frac {b\,x}{2}\right )}^4-2\,{\mathrm {tan}\left (\frac {a}{2}+\frac {b\,x}{2}\right )}^2+1\right )}-\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {a}{2}+\frac {b\,x}{2}\right )\right )}{b} \]
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